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Voici les solutions détaillées pour mettre chaque nombre complexe sous forme exponentielle reiθr e^{i\theta} (avec r>0r > 0).


Première ligne

1. (ei3π4)3(e^{i\frac{3\pi}{4}})^3

(ei3π4)3=ei⋅3⋅3π4=ei9π4(e^{i\frac{3\pi}{4}})^3 = e^{i \cdot 3 \cdot \frac{3\pi}{4}} = e^{i\frac{9\pi}{4}}

ei9π4=eiπ4e^{i\frac{9\pi}{4}} = e^{i\frac{\pi}{4}}


2. (2e−iπ6)−3(2e^{-i\frac{\pi}{6}})^{-3}

(2e−iπ6)−3=2−3⋅e−iπ6⋅(−3)=18ei3π6=18eiπ2(2e^{-i\frac{\pi}{6}})^{-3} = 2^{-3} \cdot e^{-i\frac{\pi}{6} \cdot (-3)} = \frac{1}{8} e^{i\frac{3\pi}{6}} = \frac{1}{8} e^{i\frac{\pi}{2}}


3. eiπ3(eiπ8)2\frac{e^{i\frac{\pi}{3}}}{(e^{i\frac{\pi}{8}})^2}

eiπ3eiπ4=ei(π3−π4)=ei4π−3π12=eiπ12\frac{e^{i\frac{\pi}{3}}}{e^{i\frac{\pi}{4}}} = e^{i(\frac{\pi}{3} - \frac{\pi}{4})} = e^{i\frac{4\pi - 3\pi}{12}} = e^{i\frac{\pi}{12}}


4. (eiπ3)3(eiπ2)3(e^{i\frac{\pi}{3}})^3 (e^{i\frac{\pi}{2}})^3

eiπ⋅ei3π2=ei(π+3π2)=ei5π2=eiπ2e^{i\pi} \cdot e^{i\frac{3\pi}{2}} = e^{i(\pi + \frac{3\pi}{2})} = e^{i\frac{5\pi}{2}} = e^{i\frac{\pi}{2}}


5. (e−iπ4)6(eiπ2)6(e^{-i\frac{\pi}{4}})^6 (e^{i\frac{\pi}{2}})^6

(e−iπ4⋅eiπ2)6=(ei(−π4+π2))6=(eiπ4)6=ei6π4=ei3π2\left( e^{-i\frac{\pi}{4}} \cdot e^{i\frac{\pi}{2}} \right)^6 = \left( e^{i(-\frac{\pi}{4} + \frac{\pi}{2})} \right)^6 = \left( e^{i\frac{\pi}{4}} \right)^6 = e^{i\frac{6\pi}{4}} = e^{i\frac{3\pi}{2}}


6. (3eiπ3¯)2(\overline{3e^{i\frac{\pi}{3}}})^2


Seconde ligne

7. (2ei3π4)−2¯\overline{(2e^{i\frac{3\pi}{4}})^{-2}}

(2ei3π4)−2=2−2e−i6π4=14e−i3π2=14eiπ2(2e^{i\frac{3\pi}{4}})^{-2} = 2^{-2} e^{-i\frac{6\pi}{4}} = \frac{1}{4} e^{-i\frac{3\pi}{2}} = \frac{1}{4} e^{i\frac{\pi}{2}}

14eiπ2¯=14e−iπ2\overline{\frac{1}{4} e^{i\frac{\pi}{2}}} = \frac{1}{4} e^{-i\frac{\pi}{2}}


8. (eiπ32eiπ6)−2\left(\frac{e^{i\frac{\pi}{3}}}{2e^{i\frac{\pi}{6}}}\right)^{-2}

eiπ32eiπ6=12ei(π3−π6)=12eiπ6\frac{e^{i\frac{\pi}{3}}}{2e^{i\frac{\pi}{6}}} = \frac{1}{2} e^{i(\frac{\pi}{3} - \frac{\pi}{6})} = \frac{1}{2} e^{i\frac{\pi}{6}}

(12eiπ6)−2=(1/2)−2⋅e−i2π6=22e−iπ3=4e−iπ3\left(\frac{1}{2} e^{i\frac{\pi}{6}}\right)^{-2} = (1/2)^{-2} \cdot e^{-i\frac{2\pi}{6}} = 2^2 e^{-i\frac{\pi}{3}} = 4 e^{-i\frac{\pi}{3}}


9. (eiπ3)5(ei2π3)7(e−iπ3)4\frac{(e^{i\frac{\pi}{3}})^5}{(e^{i\frac{2\pi}{3}})^7 (e^{-i\frac{\pi}{3}})^4}

ei5π3ei10π3=ei(5π3−10π3)=e−i5π3=eiπ3\frac{e^{i\frac{5\pi}{3}}}{e^{i\frac{10\pi}{3}}} = e^{i(\frac{5\pi}{3} - \frac{10\pi}{3})} = e^{-i\frac{5\pi}{3}} = e^{i\frac{\pi}{3}}


10. (2eiπ3)−3(2eiπ6)4(2e^{i\frac{\pi}{3}})^{-3} (\sqrt{2}e^{i\frac{\pi}{6}})^4

18⋅4⋅ei(−π+2π3)=12e−iπ3\frac{1}{8} \cdot 4 \cdot e^{i(-\pi + \frac{2\pi}{3})} = \frac{1}{2} e^{-i\frac{\pi}{3}}


11. (ieiπ3)6(−ei2π3)−2\frac{(i e^{i\frac{\pi}{3}})^6}{(-e^{i\frac{2\pi}{3}})^{-2}}

ei5πe−i4π3=ei(5π+4π3)=ei19π3=ei(6π+π3)=eiπ3\frac{e^{i5\pi}}{e^{-i\frac{4\pi}{3}}} = e^{i(5\pi + \frac{4\pi}{3})} = e^{i\frac{19\pi}{3}} = e^{i(6\pi + \frac{\pi}{3})} = e^{i\frac{\pi}{3}}